![we resolve the logarithmic equation log(2x^2+3)=log(x^2+5x-3) | Studying math, Learning mathematics, Systems of equations we resolve the logarithmic equation log(2x^2+3)=log(x^2+5x-3) | Studying math, Learning mathematics, Systems of equations](https://i.pinimg.com/originals/59/c3/cb/59c3cbf9edc898cd0b88298b57101a4f.png)
we resolve the logarithmic equation log(2x^2+3)=log(x^2+5x-3) | Studying math, Learning mathematics, Systems of equations
![If `log2, log(2x-1) and log(2x+3)` are in A.P., then the value of x is (A) 5/2 (C) log,5 (B) ... - YouTube If `log2, log(2x-1) and log(2x+3)` are in A.P., then the value of x is (A) 5/2 (C) log,5 (B) ... - YouTube](https://i.ytimg.com/vi/oKI2mreTRpo/maxresdefault.jpg)
If `log2, log(2x-1) and log(2x+3)` are in A.P., then the value of x is (A) 5/2 (C) log,5 (B) ... - YouTube
![log2 (9 - 2X) = 10log (3-x) Solve for x.a)0b)3c)Both (a) and (b)d)0 and 6Correct answer is option 'A'. Can you explain this answer? | EduRev Quant Question log2 (9 - 2X) = 10log (3-x) Solve for x.a)0b)3c)Both (a) and (b)d)0 and 6Correct answer is option 'A'. Can you explain this answer? | EduRev Quant Question](https://cdn3.edurev.in/ApplicationImages/Temp/695075_686c87bc-a4bb-47e6-b448-bb23730e7e8c_lg.png)
log2 (9 - 2X) = 10log (3-x) Solve for x.a)0b)3c)Both (a) and (b)d)0 and 6Correct answer is option 'A'. Can you explain this answer? | EduRev Quant Question
![IF log 2 log 2 to the power x 1 and log 2x 3 are in AP Find x - Mathematics - TopperLearning.com | sqk90tff IF log 2 log 2 to the power x 1 and log 2x 3 are in AP Find x - Mathematics - TopperLearning.com | sqk90tff](https://images.topperlearning.com/topper/tinymce/integration/showimage.php?formula=dd9f9be39888bc51e0628640bbfa9469.png)
IF log 2 log 2 to the power x 1 and log 2x 3 are in AP Find x - Mathematics - TopperLearning.com | sqk90tff
![Solving Log Equations 1. log 2 72 = log 2 x + log 2 12 log log 2 12 = log 2 x x = x = 8 log 2 x = log 8 xlog2 = log 8 x = 3 3. xlog7 = 2log ppt download Solving Log Equations 1. log 2 72 = log 2 x + log 2 12 log log 2 12 = log 2 x x = x = 8 log 2 x = log 8 xlog2 = log 8 x = 3 3. xlog7 = 2log ppt download](https://images.slideplayer.com/33/10126461/slides/slide_6.jpg)
Solving Log Equations 1. log 2 72 = log 2 x + log 2 12 log log 2 12 = log 2 x x = x = 8 log 2 x = log 8 xlog2 = log 8 x = 3 3. xlog7 = 2log ppt download
![How to solve for x in this equation log base 3 (x^2 + x - 6) = log base 3 (x ^2 + 7x + 12) - 2/3log base 9 (8) - Quora How to solve for x in this equation log base 3 (x^2 + x - 6) = log base 3 (x ^2 + 7x + 12) - 2/3log base 9 (8) - Quora](https://qph.fs.quoracdn.net/main-qimg-92b2cdeba8dbe90bce9405c7d3901ace.webp)